Answer:
3y=x+5
Step-by-step explanation:
The slope of the line is (1/3). The equation of the line is y=(1/3)x+5/3 or 3y=x+5
This is the answer to your following question. Good luck!
Answer:
Point W
Step-by-step explanation:
The intersection of two lines is a point. In this case, the point is named W.
Answer:
(a) 3.8
Step-by-step explanation:
The Law of Sines can be used to find a missing side length in a triangle where the angles are known and at least one side is given. It tells you the ratio of side lengths is equal to the ratio of the sines of their opposite angles. In effect, longer sides are opposite larger angles.
__
<h3>compare angles</h3>
The given side length (DE=3) is opposite given angle F=50°. The unknown side length EF is opposite larger angle D=75°.
<h3>compare sides</h3>
Since the unknown side is opposite a larger angle than the other angle given, the length of the unknown side will be longer than the side given.
EF > DE
EF > 3
Only one answer choice satisfies this inequality.
EF = 3.8
__
<em>Additional comment</em>
If you want to do the actual computation, we have ...
EF/sin(D) = DE/sin(F)
EF = DE·sin(D)/sin(F) = 3·sin(75°)/sin(50°) ≈ 3.7828
EF ≈ 3.8
Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width 
: 
- Area of triangle with base
and height 
: 
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then 
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of 
units squared, and the both of them have a total area of 
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of 
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)
