What is the solution of (x-9)^2/3=25 algebraicallt

1 answer:

7 0

$\bf \cfrac{(x-9)^2}{3}=25\implies (x-9)^2=75\implies \sqrt{(x-9)^2}=\sqrt{75}\implies x-9=\pm\sqrt{75} \\\\\\ x=\pm \sqrt{75}+9\implies x\approx \begin{cases} 17.66\\ -0.34 \end{cases}$

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ASAP Please help. Thank You!!! :)

liraira [26]

#25.
Convert the fractional numbers into decimals for easier comparison.
3 2/3 is approximately 3.66
-4 2/5 is approximately -4.4
We now have: 3, 3.66, -4.2, -4.4
In order: -4 2/5, -4.2, 3, 3 2/3

#26.
All positive numbers are greater than negative numbers.
When comparing two negative numbers, the one with the larger absolute value, will be less.
So (G) is correct

#27.
25 = m + 6.3
25 - 6.3 = m + 6.3 - 6.3
m = 18.7

#28.
h = 3.2-1.6 = 1.6

#29.
x = 15.6 - 9.8 = 5.8

#30
p = 17 - 4.5 = 12.5

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