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alukav5142 [94]
2 years ago
8

17 calculators for 340$ or 200 calculators for 3,600.

Mathematics
1 answer:
solong [7]2 years ago
3 0
The better deal is the 200 calculators
You might be interested in
Find the smallest positive $n$ such that \begin{align*} n &\equiv 3 \pmod{4}, \\ n &\equiv 2 \pmod{5}, \\ n &\equiv
Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number x such that taking it mod 4, 5, and 7 leaves the desired remainders:

x=3\cdot5\cdot7+4\cdot2\cdot7+4\cdot5\cdot6

  • Taken mod 4, the last two terms vanish and we have

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod4

so we multiply the first term by 3.

  • Taken mod 5, the first and last terms vanish and we have

x\equiv4\cdot2\cdot7\equiv51\equiv1\pmod5

so we multiply the second term by 2.

  • Taken mod 7, the first two terms vanish and we have

x\equiv4\cdot5\cdot6\equiv120\equiv1\pmod7

so we multiply the last term by 7.

Now,

x=3^2\cdot5\cdot7+4\cdot2^2\cdot7+4\cdot5\cdot6^2=1147

By the CRT, the system of congruences has a general solution

n\equiv1147\pmod{4\cdot5\cdot7}\implies\boxed{n\equiv27\pmod{140}}

or all integers 27+140k, k\in\mathbb Z, the least (and positive) of which is 27.

3 0
3 years ago
Writing linear equations <br> Writing linear equations
trapecia [35]
What is the question?
4 0
2 years ago
Read 2 more answers
F(n) = f(n – 1) + f(n – 2); f(1) = 2; f(2) = 1.
Alex Ar [27]

f(n) is the nth term

Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)

The term just before nth term is f(n-1)

The term just before the (n-1)st term is f(n-2)

----------------

For example, let's say n = 3 indicating the 3rd term

n-1 = 3-1 = 2

n-2 = 3-2 = 1

So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.

f3) = third term

f(2) = second term

f(1) = first term

8 0
3 years ago
Expanded form of 680,705
denis23 [38]

\huge\boxed{600,000 + 80,000 + 700 + 5}

To find expanded form, we need to split up the digits. When you do that, you take one digit and cut off everything to the left of it, then make everything to the right zeros.

600,000 + 80,000 + 0 + 700 + 0 + 5

We don't need to keep the zeros.

\boxed{600,000 + 80,000 + 700 + 5}

We can check this by adding the numbers back up to get 680,705.

680,000 + 700 + 5

680,700 + 5

680,705

6 0
3 years ago
Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. Se
sesenic [268]

Answer:

Log_5 12=1.54

Step-by-step explanation:

We are given that

Log_5 12

We have to find the value of given logarithms by using change-base formula

Base-change formula:

log_a b=\frac{Log_x b}{Log_x a}

Where x=New base

Using the formula then, we get

Log_5 12=\frac{log_{10} 12}{log_{10} 5}

Substitute the values log_{10}12=1.079, log_{10}5=0.699

Then,we get

Log_5 12=\frac{1.079}{0.699}

Log_5 12=1.54

3 0
3 years ago
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