No, because something extra is being added/divided and there are too many variables on one side
R(x) = 60x - 0.2x^2
The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150
Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
I think the answer it would be D
Answer:
a - b = 12
Step-by-step explanation:
Given
= 12 ← factor the numerator
a² - b² ← is a difference of squares and factors as
a² - b² = (a - b)(a + b)
Thus
= 12
Cancel the common factor (a + b) on numerator/ denominator, thus
a - b = 12
Let the number of hours be x.
70 + 80x < 100x
20x > 70
x > 3.5
