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Veronika [31]
3 years ago
7

Draw a number line that represents 7+(-4).

Mathematics
1 answer:
tekilochka [14]3 years ago
3 0
You start from negative 7 in number line and you go left 4
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15/20 times 1/4 thank me if u like brainly
MaRussiya [10]

Answer: 3/16

Step-by-step explanation: To multiply fractions, first multiply across the numerators and then multiply across the denominators.

\frac{15}{20} × \frac{1}{4} = ?

15 × 1 = 15

20 × 4 = 80

\frac{15}{20} can be reduced by dividing both the numerator and denominator by the Greatest Common Factor which is 5.

15 ÷ 5 = 3

80 ÷ 5 = 16

Therefore, \frac{15}{20} × \frac{1}{4} = \frac{3}{16}

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3 years ago
How to find components of a vector given magnitude and angle?
Zanzabum
<span>1. Find the magnitude and direction angle of the vector.
2. Find the component form of the vector given its magnitude and the angle it makes with the positive x-axis.
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What is 3z + 2 when z = 2?
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Answer:

b 8

Step-by-step explanation:

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3(2)+2

4 0
3 years ago
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11. The test scores of 20 students are shown below.
daser333 [38]
Your answer would be 10.6
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2 years ago
e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv
Naddika [18.5K]

Answer:

The answer is \{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}

Step-by-step explanation:

Remember that a reflexive relation R\subset \mathcal{P}(X), where \mathcal{P}(X) is the power set of X, is one which conteins the ordered pairs of the form (a,a), for a\in X.

So, As the reflexive and transitive closure of R (that we will denote by \overline{R}) is in particular reflexive, we must add to R  the elements \{(1,1) , (2,2),(3,3),(4,4) \}

A transitive relation R is one in which if the pair (a,b) and the pair (b,c) are in there, then the pair (a,c) must be there too.

So, to complete the relation R to be reflexive and transitive we must add the pair (1,3) (because (1,2),(2,3) are in R), the pair (2,4), and the pair (1,4) because we added the pair (2,4).

Therfore we have that \overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}.

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