The options for the first one are:

Mathematics

1 answer:

Kay [80]3 years ago

3 0

Answer:

first one add

second one multiply by

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PLEASE HELP im dying over here

Iteru [2.4K]

$\dfrac{x}{24\sqrt{2}}=\cos45^\circ\\\\\\\dfrac{x}{24\sqrt{2}}=\dfrac{\sqrt{2}}{2}\qquad\qquad\qquad\text{(cross multiply)}\\\\\\2x=24\sqrt{2}\cdot\sqrt{2}\\\\2x=24\cdot2\quad|:2\\\\\boxed{x=24}$

7 0

3 years ago

Please help.

denis23 [38]

9514 1404 393

Answer:

Angle 1 = 139°
Angle 2 = 41°
x = 29; exterior angle = 131°

Step-by-step explanation:

These problems let you make use of the fact that the sum of the remote interior angles is equal to the exterior angle.

1. 53° +86° = ∠1

139° = ∠1

2. ∠2 +92° = 133°

∠2 = 133° -92°

∠2 = 41°

3. (x +9)° +93° = (4x+15)°

87 = 3x . . . . . . . . . . . . . . . . subtract x+15°

29 = x . . . . . . . divide by 3

The exterior angle is ...

(4x +15)° = (4·29 +15)° = 131° . . . exterior angle

3 0

3 years ago

Brown has own bakery he baked 5 cakes per day due to occasional christmas story to be in the whole christmas week how many cakes

Lena [83]

she would make 35 cakes

8 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,