Answer:
Circle
Step-by-step explanation:
The definition of a circle is the set of points equidistant from a given point. Since all points are equidistant from this given point, the center, the radius is the same all throughout the circle; the only way to have all points equidistant is to travel around the center 360 degrees.
Answer:
The answer is 24 i believe
Step-by-step explanation:
The formula to find the volume)The volume of cylinder will be = V\pi r^2 h
V = 1/3times3.14times5times5times10=261.67 cubic cm.
Now, the number of cones needed to fill the cylinder will be = 6280/261.67=23.999 = 24
Another way to figure
this out is n×1/3×5×5×10=10×10×20
n=2000×3÷250
n=24
In simple words, the inverse function is obtained by swapping the (x, y) of the ... For example, to check if f(x) = 3x + 5 is one to one function given, f(a) = 3a + 5 and f(b) ... –9)}? Function h is not one to one because the y- value of –9 appears more than once. ... (2x − 1) [(4 + 5x)/ (2x − 1) + 4]/ [2(4 + 5x)/ (2x − 1) − 5] (2x − 1).
Answer:
- <u>The zero is x = 5, and it represents that the diver will enter the pool's surface 5 feet in front of the diving board.</u>
Explanation:
The function is f(x) = - x² - 5x + 50.
Where:
- f(x) is the vertical distance of a diver from a pool's surface, and
- x is the horizontal distance of a diver from the diving board.
A zero of f(x) represents a point where the diver is at the surface of the pool. There might be two possible zeros.
Solve the equation to determine the zeros:
- Multiply both sides by - 1: x² + 5x - 50
- Factor: (x + 10) (x - 5) = 0
- Use zero product property: x + 10 = 0 or x - 5 = 0
- From x + 10 = 0 you get x = - 10
- From x - 5 = 0 you get x = 5.
- The negative zero is not valid as it would be a point behind the diving board, so the meaningful zero is when x = 5, meaning that the diver will touch the surface of the pool at 5 feet in front of the diving board.
A and B, when dividing the two numbers for A, the answer is negative 4. And as for B, the answer comes out to negative 3 I believe. <span />
