Odd numbers end with 1 or 3 or 5 or 7 or 9
alrighty, the last number can be 1 or 3 or 7 or 9 (we aren't given 5 in the set)
4 choices for the last number
for the other 2 numbers, we can use any other numbers
6 numbers in the set
6 choices for the first digit
5 for the 2nd
4 for the 3rd digit
so there are 6*5*4 or 120 different odd numbers that can be constructed withthe given numbers in the set
2x+79+32=180
2x+111=180
2x=69
x=34.5
–6<span>x2</span> – x + 2 = –1(6<span>x2</span> + x – 2)<span>. I hope this helped ^^</span>