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Lena [83]
3 years ago
13

What is the area of a square rug that measures 6 feet on a side? 3 square feet 24 square feet 12 square feet 36 square feet

Mathematics
2 answers:
Illusion [34]3 years ago
6 0
36ft is the area of a square rug that measures 6ft on a side.
QveST [7]3 years ago
4 0
Well we know the area of a square is l*w, or s^2. So we can use s^2 where s=6 in your case. Now 6^2 is 6*6, which is 36.

So the area of a square rug that measures 6 feet is 36 feet

Answer= 36 feet
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The measure of two vertical angles are 6x - 22 and 4x + 2. Find x.
maks197457 [2]
Vertical angles are congruent...they are equal....so set them equal to each other and solve for x

6x - 22 = 4x + 2
6x - 4x = 2 + 22
2x = 24
x = 24/2
x = 12 <==



6 0
3 years ago
25 POINTS
uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)


Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

4 0
3 years ago
Read 2 more answers
which will have a higher effective interest rate a payday loan for $1700 that is due in 16 days with a fee of $100, or a payday
Fantom [35]
1700 that is due in 14 days with a fee of 100$ because it’s a shorter time period
7 0
3 years ago
Read 2 more answers
The club's total number of members will grow exponentially each month. She uses the given expression to model the number of club
mihalych1998 [28]

Answer:

1.8 represents the initial number of the club members in hundreds.

Step-by-step explanation:

* Lets revise the exponential grows

- If a quantity grows by a fixed percent at regular intervals,

 the pattern can be depicted by this function.

- The function of the exponential growth is:

  y = a(1 + r)^x

# a = initial value (the amount before measuring growth)

# r = growth rate (most often represented as a percentage and

  expressed as a decimal)

# x = number of time intervals that have passed

* Now Lets study the problem to solve it

- The club's total number of members will grow exponentially

  each month

- The expression to model the number of club members, in

  hundreds, after advertising for t months is

  1.8(1.02)^12t

* Lets compare between this model and the function above

# a = 1.8 ⇒ initial number of members in hundreds

# r = 1.02 - 1 = 0.02 ⇒ growth rate

# x = 12t ⇒ number of time intervals

* 1.8 represents the initial number of the club members in hundreds.

6 0
4 years ago
0-6
dybincka [34]
<h3>Given :-</h3>
  • Pranav ran 20.3 km more than Branda

  • Pravin ran 38.6 km

\\  \\

To find :

  • No. of kilometers did Brenda run.

\\  \\

<h3>Let :</h3>

  • No. of kilometers ran by Brenda be x.

\\  \\

<h3>Solution:</h3>

\\  \\

Equation formed:-

\\  \\

Total distance covered by Pravan = More distance covered by Pravan + distance covered by Brenda.

Therefore:-

\\  \\

\leadsto \sf38.6 = 20.3 + x

Write the equation

\\  \\

\leadsto \sf38.6 - 20.3 =x

When we transfer 20.3 to left side the positive sign (+) will change into negative sign (–)

\\  \\

\leadsto \sf x = 38.6 - 20.3

Arrange the equation because x is always represented at left side.

\\  \\

\leadsto \boxed {\pmb{\sf x = 18.3}}\star

After subtracting 38.6 with 20.3 we will get result as 18.3 .

\\  \\

\therefore \red{ \underline{  \pmb{\frak{Distance  ~ covered ~by ~Brenda~ is ~equal ~to~18.3~kilometers}}}}

7 0
3 years ago
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