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3 years ago

Find the missing length to the nearest tenth.

Mathematics

1 answer:

Verdich [7]3 years ago

5 0

Answer:

6.8

Step-by-step explanation:

a^2 + b^2 = c^2

6.6^2 + b^2 = 9.5^2

43.56 + b^2 = 90.25

b^2 = 90.25 - 43.56

b^2 = 46.69

(take square root of both sides)

b = 6.8

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A motorboat takes 3 hours to take a 60 mile trip downstream. It takes 5 hours to make the same trip upstream. Let x represent th

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THE RATE OF THE BOAT BELOW IS 5: 100

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3 years ago

Identify the closest perfect squares less than and greater than the radicand below, respectively.

wariber [46]

It would be A because they’re both perfect squares

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3 years ago

Find the value of each expression. Show your work.

Verdich [7]

Answer:

$A) (1.2)^{2} = 1.44$

$B)2^ 3+17-(3\times 4) = 13$

$C)\frac{(9)^2}{(3)^3} = 3$

Step-by-step explanation:

Here, the given expressions are:

A) $(1.2)^{2}$

Solving this, we get

$(1.2)^{2} = 1.2 \times 1.2 = 1.44$

⇒ $(1.2)^{2} = 1.44$

B) $2^ 3+17-(3\times 4)$

Now, solving this, we get

$2^ 3+17-(3\times 4) = (2 \times 2 \times2) + (17 -12)\\=8 + 5 = 13$

⇒ $2^ 3+17-(3\times 4) = 13$

C) $\frac{(9)^2}{(3)^3}$

Simplifying this, we get

$\frac{(9)^2}{(3)^3} = \frac{(9\times9)}{(3 \times 3\times3)} = 3$

⇒ $\frac{(9)^2}{(3)^3} = 3$

4 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

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4 years ago

Whoever gets it right and first get Brainlest

Ivenika [448]

Answer:

The answer is -5.44

5 0

3 years ago

Read 2 more answers