If anyone can help thanks (the pdf below is the work)

Number 6 mainly and any other if you want to help:) looka t the pic

soldier1979 [14.2K]

Let the amount B pays be £x
So,
A pays £125
B pays £x
They pay in the ration 3:2
Therefore,
125/x = 3/2
Cross multiplying we get,
125 x 2 = 3x
3x = 250
x = £63.33

3 0

3 years ago

What is a fraction between -3/4 and -1/3

Yuki888 [10]

let's firstly convert both fractions with the same denominator, by simply multiplying each fraction by the other's denominator, let's proceed.

$\bf -\cfrac{3}{4}\cdot \cfrac{3}{3}\implies \boxed{-\cfrac{9}{12}}~\hfill -\cfrac{1}{3}\cdot \cfrac{4}{4}\implies \boxed{-\cfrac{4}{12}} \\\\[-0.35em] ~\dotfill\\\\ \boxed{-\cfrac{9}{12}}~~,~~\stackrel{-\frac{2}{3}}{-\cfrac{8}{12}}~~,~~-\cfrac{7}{12}~~,~~\stackrel{-\frac{1}{2}}{-\cfrac{6}{12}}~~,~~-\cfrac{5}{12}~~,~~\boxed{-\cfrac{4}{12}}$

5 0

3 years ago

Read 2 more answers

Find the value of x please help

____ [38]

using angle sum property

we get

110+35+(x+12)=180

(x+12)=180-145

(x+12)= 35

x= 35-12

x= 23

3 0

2 years ago

Read 2 more answers

96 sq meters

Vsevolod [243]

Answer:

84 sq meters

Step-by-step explanation:

1. Approach

In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.

2. Area of Region 1

As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.

Length * width

6 * 3

= 18

3. Area of Region 2

In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.

Length * width

= 12 * (8 - 3)

= 12 * 5

= 60

4. Area of Region 3

In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.

Length * width

= 2 * 3

= 6

5. Total area

Now add up the area of each region to find the total rea,

(Region 1) + (Region 2) + ( Region 3)

= 18 + 60 + 6

= 84

7 0

3 years ago

How does the speed of a runner vary over the course of a marathon (a distance of 42.195 km)? Consider determining both the time

Tom [10]

Answer:

The observed typical difference value of mode is 100 seconds approximately.

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

Step-by-step explanation:

Fundamentals

Consider that there are x favorable cases to an event E, out of a total of n cases. Then, the probability of that event is written as:

P(E)=

Total number of cases /Number of favorable cases = x/n

A histogram is constructed for continuous data, which is divided into classes called bins. The shape of the distribution can be determined from the histogram.

step 1

The provided histogram indicates time difference on xx -axis and frequency of runners on yy -axis. To determine the typical difference value, identify the peaks of the graph.

The histogram is skewed towards right side. The graph indicates that there are few outliers around 700 seconds. For a typical difference value, the value of mode is considered.

The graph indicates that the value of mode is 100 seconds approximately.

The observed typical difference value of mode is 100 seconds approximately.

Explanation

From the histogram, the typical difference value is obtained on the basis of guessing the value of mode which has been approximated to be around 100 seconds.

Step 2

From the histogram, it can be estimated that there are around 10 runners which has negative difference which means approxi8matley 10 runners ran the late distance more quickly than the early distance,

The approximate sample size can be calculated as:

Sample size=90+190+180+160+120+80+60+40+30+20

Thus, the proportion of runners is obtained as:

\begin{array}{c}\\p = \frac{{\left( \begin{array}{l}\\{\rm{Number of runners who has }}\\\\{\rm{negative time difference}}\\\end{array} \right)}}{{{\rm{Total sample size}}}}\\\\ = \frac{{10}}{{970}}\\\\ = 0.01\\\end{array}

p= Number of runners who has

negative time difference

Total sample size

=10/970

=0.001

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

EXPLANATION

The obtained proportion is 0.01. It indicates that there are approximately 1% of the runners who ran late distance more quickly than the early distance is very few.

3 0

3 years ago