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Alexxandr [17]
3 years ago
9

The third day Jim plans to snow board. The boards rent for $8.95 an hour, and the boots

Mathematics
1 answer:
olganol [36]3 years ago
4 0

Answer: $113.55

Step-by-step explanation:

add up the cost of the lesson, boots, board, and ticket

the lesson costs $33.80 and the ticket costs $25, these cover the whole day so no need to be multiplied. the boots cost $2 and the board costs $8.95 each hour, jim will need to pay the cost of both 5 times for 5 hours.

here is the equation to solve

33.80 + 5(8.95 + 2.00) + 25 =

33.80 + 5(10.95) + 25 =

33.80 + 54.75 + 25 =

33.80 + 79.75 = 113.55

the total cost is $113.55

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Help me solve problem one please.
max2010maxim [7]

Answer: His temperature is 99°F

Step-by-step explanation:

Let's state what we know:

Steve's temperature was initially 102°F

Later it dropped 3°F lower

Since his temperature decreased we need to subtract 3 from 102 to see what his temperature is now

102-3=99

4 0
2 years ago
Can somebody help me with this problem!? i need help ahh
slamgirl [31]

for these kinds of problems the outside angle always equals the opposite 2. meaning angle x=64+70 which is 134 degrees. you can double check this because all triangles equal 180 degrees. meaning that the last angle in the triangle is 46. 46+70+64=180.

so your answer is 134.

hope this helps :)

6 0
3 years ago
Read 2 more answers
of the students in Ms. Danver's class, 6 walk to school. This represents 30% of her students.How many students are in Ms. Danver
Andrews [41]
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8 0
3 years ago
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X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
3 years ago
What is the value of y
Reil [10]
All angles in a triangle add up to 180
So 79+37=116
180-116=64
Y=64
Hope this helps
5 0
3 years ago
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