Which statement defines the term markup

1 answer:

3 0

Im thinking C . <span>extra amount added to the marginal cost to arrive at the selling price because you're marking up the price because its </span>more for you and if it was cheaper you'd lose money.

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Marvin counts six $5 bills. write each value that he counts. what pattern do you see in the one digits of the values he counts?

spin [16.1K]

Answer: If the number of bills counted is odd, the ones digit is 5; if the number of bills is even, the ones digit is 0.

Explanation

1) Simulate the counting of the bills:

number of bills counted          value            ones digit

1                                             5                         5

2                                             5 + 5 = 10       0

3                                             10 + 5 = 15         5

4                                             15 + 5 = 20         0

5                                              20 + 5 = 25        5

6                                              25 + 5 = 30        0

2) Pattern: you can see that the ones digit alreternate: 5, 0, 5, 0, 5, 0, ...

If the number of bills counted is odd the ones digit is 5, if the number of bills is even the ones digit is 0.

4 0

4 years ago

A procurement specialist has purchased 25 resistors from vendor 1 and 30 resistors from vendor 2. Let

Ulleksa [173]

Answer:

Normal Distribution

Standard error = 0.473

Step-by-step explanation:

We are given the following information:

A procurement specialist has purchased 25 resistors from vendor 1 are assumed to be normally distributed with mean 100 ohms and standard deviation 1.5 ohms.

$x_{1,1}, x_{1,2}, ... , x_{1,25}\\\mu_{1} = 100\\\sigma_1 = 1.5$

A procurement specialist has purchased 30 resistors from vendor 2 are assumed to be normally distributed with mean 105 ohms and standard deviation 2.0 ohms.

$x_{2,1}, x_{2,2}, ... , x_{2,30}\\\mu_{2} = 105\\\sigma_1 = 2.0$

The difference of two independent normally distributed random variables is normal, with its mean being equal to the difference of the two means, and its variance being the sum of the two variances.

Thus, the sampling distribution of $X_1-X_2$ is a normal distribution.