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melamori03 [73]
3 years ago
9

Please solve this and show how you did. Thanks!!

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0
4x+6<-6
-6 -6
-------------
4x<-12

Then you divide 4x on both sides so 4x divided by 4x and -12 divided by 4x. When dividing this the 4 isnt a negative so you dont flip the "<" so it stays the same. The answer would be x<-3
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Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

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                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}

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Step-by-step explanation:


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Given:

Bobby put 1/3 of his lawn mowing money into his savings

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He has $12 left.

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Step-by-step explanation:

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