Roots: ( -2/5 , 0 ) ( 1 , 0 )
Domain: x∈ R
Maximum: ( 3/10 , 49/ 20 )
Vertical intercept: ( 0 , 2 )
(you can also download the app photomath the app is really helpful)
<span>Answer:
P=27
Q=10
TC=280
TC=FC+VC
FC=30
VC=280-30=250
TR=Q*P=10*27=270
Profit=TR-TC=270 - 280= -10
In short-tun Bob should continue mow lawns because he covers fixed costs (overvice instead of loss -10 he would had loss amounting fixed costs - 250)
In long-run he should close production.</span>
4:6 = 2:3
2:3 times 7 equals 14:21
Hope this helped!
9514 1404 393
Answer:
t ≈ 0.590 s (ascent); 5.532 s (descent)
Step-by-step explanation:
We are interested in the values of t when s=16.
s = 30t -4.9t²
4.9t^2 -30t +16 = 0 . . . . . substitute 16 for s; put in standard form
The quadratic formula can be used to find the solutions:
t = (-(-30) ±√((-30)² -4(4.9)(16)))/(2(4.9))
t = (30 ±√586.4)/9.8 ≈ 0.59023, 5.53221 . . . . seconds after launch
a) It will take 0.590 seconds to reach 16 m height initially.
b) It will take 5.532 seconds to return to 16 m height on descent.
Answer:
<u>SA = 189 cm^2</u>
Step-by-step explanation:
What you're going to want to do is calculate the surface area of each type of side (triangle or rectangle) then add them up accordingly!
Starting with triangles: area = 1/2 * l * h
So, in this scenario its (1/2) * 6 * 4 , or half of 24, which is 12 cm^2
Since we have two triangular sides, that totals to 24 cm^2.
Then the rectangular sides: area = l*h
so, 5*11 = 55 cm^2
We have three rectangular sides, totalling 165 cm^2
165+24 = 189 cm^2
