If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
(10.78483, 12.61517)
Step-by-step explanation:
It is given that the genera mangers of few hotels were sent some questionnaires for conducting a study for the career paths in the major hotel chains of the United States.
Number of hotels = 160
Number of response received = 103
The average number of years these general mangers was in their current hotels, 
= 11.7 years
Confidence Interval, CI = 0.99
Therefore,
a = 0.01, |Z(0.005)| (from standard normal table)
∴ 99% of CI = 
Answer:
d
Step-by-step explanation:
Act like it's a rectangle. The height is 10 because 7+3=10 and the length it 27. Multiply them for the are and you get 270 in. Then multiply 6x7=42 because that's the are of the space that is missing from the imaginary rectangle. Multiply by 2 (84 in.) because there are 2 missing spaces and subtract from 270= 186 inches is your answer.
Answer:
The place value of 1 in 1,234,567,890 is <u>1</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>.</u>
