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ANEK [815]
3 years ago
10

Solve for x: −2x + 5 < 7 x > −1 x < −1 x > −6 x < −6

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

- 2x + 5 < 7

- 2x  < 7 - 5

- 2x < 2

- x <  \frac{2}{2}

- x < 1

x <  - 1

So, Answer is <em><u>"</u></em><em><u> </u></em><em><u>x<</u></em><em><u> </u></em><em><u>-</u></em><em><u>1</u></em><em><u>"</u></em>

<em>Hope</em><em> it</em><em> helps</em><em> you</em><em>.</em><em>.</em><em>.</em>

<em>A</em><em>nswered </em><em>by </em><em>Benjemin</em><em> ☺️</em>

<em>✅</em>

mars1129 [50]3 years ago
5 0

hopefully this helps :)

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Conditional Probability

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P(B|A) = \frac{P(A \cap B)}{P(A)}

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Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

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If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

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0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

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p = P(A) + P(B) - P(A \cap B)

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