Answer:
bearing of A from C is - 65.24°
the distance |BC| is 187.84 m
Step-by-step explanation:
given data
girl walks AB = 285 m (side c)
bearing angle B = 78°
girl walks AC = 307 m (side a)
solution
we use here the Cosine Law for getting side b that is
ac² = ab² + bc² - 2 × ab × cos(B) ...............1
307² = 285² + x² - 2 × 285 cos(78)
x = 187.84 m
and
now we get here angle θ , the bearing from A to C get by law of sines
sin (θ) =
sin (θ) = 0.5985
θ = 36.76°
and as we get here angle BAC that is
angle BCA = 180 - ( 36.76° + 78° )
angle BCA = 65.24°
and here negative bearing of A from C so - 65.24°
The quadratic formula is:

and

Let's identify our a, b, and c values:
a: -1
b: 1
c: 12
Plug in the values for a, b, and c into the equation. Let's do the first equation:

Simplify everything in the radical:

Simplify the radical:

Combine like terms:

Simplify:

This is one solution, now, let's solve for the other equation:
Since when simplified, everything is the same except the subtraction sign, we can skip the simplification again and change the sign to subtraction:

Combine like terms:

Simplify:

Your final answers are:


4 tens and 10 ones is 410
412 movies
Option A:
is the solution
Explanation:
The solution of the given inequality is the set of all the possible values of x.
The graph shows the number line in which the shaded region is from the right of -4 and the arrow of solution goes to infinity.
Also, There is a closed circle at the point -4.
This means that -4 is included in the solution set.
The solution to the inequality is the set of all the real values which are greater than or equal to -4.
Thus, the solution is x ≥ -4
Hence, the solution is 
Hey, there!!
Given that:
y = 3x.........(i)

Putting the value of y in equation (ii)

=0


Therefore,
Either Or
(x+4)=0 (x-4)=0
x= -4 x= 4
so, x= (+ -)4
And if you wanna get value of y, just keep value of x in equation (i).
y= 3x
y= (3×4) or (3×-4)
y= 12 or -12
{As it is the quadratic equation it has two values. }
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>