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devlian [24]
3 years ago
14

Barbara plotted an elevation below sea level on a number line and labeled it A. She plotted point B above o, a distance that is

exactly as far from 0 as point A is. Explain what you know about point B.
Mathematics
2 answers:
stellarik [79]3 years ago
7 0

Answer: Because Point A is negative and the same distance below 0 on the number line as Point B is above it, Point B is both positive and the opposite of Point A.




Juliette [100K]3 years ago
5 0

Answer:

According to Barbara's plot, the number line A, is above sea level, therefore, it's a positive line, in positive range.

On the other hand, the number line B has the same distance but in the opposite direction, is downwards the zero point. So, this means the B line is below sea level, because is in positive range. That's what we can deduct from this, because the characterization Barbara is doing is related to sea level.

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2) A girl starts from a point A and walks 285m to B on a bearing of 078°. She then walks due south to a point C which is 307m fr
adelina 88 [10]

Answer:

bearing of A from C is - 65.24°

the distance |BC| is 187.84 m

Step-by-step explanation:

given data

girl walks AB = 285 m (side c)

bearing angle B = 78°

girl walks AC = 307 m (side a)

solution

we use here the Cosine Law for getting side b that is

ac² = ab² + bc² - 2 × ab × cos(B)     ...............1

307² = 285² + x²  - 2 × 285 cos(78)

x = 187.84 m

and

now we get here angle θ , the bearing from A to C get by law of sines

sin (θ) = \frac{187.84}{307} \times sin(78)

sin (θ) =  0.5985  

θ = 36.76°

and as we get here angle BAC that is

angle BCA = 180 - ( 36.76° + 78° )

angle BCA = 65.24°

and here  negative bearing of A from C so - 65.24°

7 0
3 years ago
H (t) = -t2 + t + 12 <br> Solve by using quadratic formula
Sedaia [141]

The quadratic formula is:

x=\frac{-b+\sqrt{(b)^2-4(a)(c)}}{2a}

and

x=\frac{-b-\sqrt{(b)^2-4(a)(c)}}{2a}

Let's identify our a, b, and c values:

a: -1

b: 1

c: 12

Plug in the values for a, b, and c into the equation. Let's do the first equation:

x=\frac{-1+\sqrt{(1)^2-4(-1)(12)}}{2(-1)}

Simplify everything in the radical:

x=\frac{-1+\sqrt{49}}{-2}

Simplify the radical:

x=\frac{-1+7}{-2}

Combine like terms:

x=\frac{6}{-2}

Simplify:

x=-3

This is one solution, now, let's solve for the other equation:

Since when simplified, everything is the same except the subtraction sign, we can skip the simplification again and change the sign to subtraction:

x=\frac{-1-7}{-2}

Combine like terms:

x=\frac{-8}{-2}

Simplify:

x=4

Your final answers are:

x=-3

x=4

8 0
3 years ago
Read 2 more answers
Please help me to solve the problems
OLga [1]
4 tens and 10 ones is 410
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3 0
3 years ago
Write the solution to the given inequality in interval notation.
DIA [1.3K]

Option A:  $[4, \infty)$ is the solution

Explanation:

The solution of the given inequality is the set of all the possible values of x.

The graph shows the number line in which the shaded region is from the right of -4 and the arrow of solution goes to infinity.

Also, There is a closed circle at the point -4.

This means that -4 is included in the solution set.

The solution to the inequality is the set of all the real values which are greater than or equal to -4.

Thus, the solution is x ≥ -4

Hence, the solution is $[4, \infty)$

4 0
3 years ago
Solve the system of equations​
Solnce55 [7]

Hey, there!!

Given that:

y = 3x.........(i)

y =  {x}^{2}  + 3x - 16.......(ii)

Putting the value of y in equation (ii)

{3x}^{} =  {x}^{2}  + 3x - 16

{x }^{2}  - 16=0

( {x)}^{2}  -  {4}^{2}  = 0

(x + 4)(x - 4) = 0

Therefore,

Either Or

(x+4)=0 (x-4)=0

x= -4 x= 4

so, x= (+ -)4

And if you wanna get value of y, just keep value of x in equation (i).

y= 3x

y= (3×4) or (3×-4)

y= 12 or -12

{As it is the quadratic equation it has two values. }

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
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