Answer:



Step-by-step explanation:
The given equation is

If we isolate
, we can find the constant

So, the constant is
.
Another proportions that have the same constant as the given equation are



If that is 6-3(log2n)=0 then how you would go about solving it is by looking at log2n like x. In this case, for 6-3x=0, x would have to =2. So log2n has to =2. If log2n=2 and we assume that the base is 10 (because if there is no written base on a log then it is 10) then we need to rewrite the log to exponential form. Rewritten it's 10^2=2n. 100=2n, divide both sides by 2 and you get n=50.
Answer:
x=
Step-by-step explanation:
Q= illumination
I = intensity
Q= I/d^2
Q_total = 
= 
now Q' = 0
⇒I
x=![\frac{16}{\sqrt[3]{2}+1 }](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B%5Csqrt%5B3%5D%7B2%7D%2B1%20%7D)
[/tex]
x=
is the required point
What I did is to add 0.52
+0.15
then try to find what could equal the same amount with 0.52