Answer:
<em>1.3%</em>
When entered into a calculator, 12/890 (the chance of a given calculator being defective) = 0.01348...
As a percent this is 100*0.01348% = 1.348%, and to the nearest tenth, 1.3%
Answer: 4/2
Step-by-step explanation: Rise over run. From point S to R it goes up 4 and over 2.
For this problem, the confidence interval is the one we are looking
for. Since the confidence level is not given, we assume that it is 95%.
The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n
Where:
<span>
</span>
α= 5%
α/2
= 2.5%
t
0.025, 19 = 2.093 (check t table)
n
= 20
df
= n – 1 = 20 – 1 = 19
So plugging in our values:
8.41 ± 2.093 * 0.77 √ 1 + 1/20
= 8.41 ± 2.093 * 0.77 (1.0247)
= 8.41 ± 2.093 * 0.789019
= 8.41 ± 1.65141676
<span>= 6.7586 < x < 10.0614</span>
