How many units is it from 3 to -4 on a number line?
2 answers:
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Answer:
A.) x-y=2 and x+2y=-2
Step-by-step explanation:
For option A, we have:
x-y=2
x+2y=-2
Subtract the first equation from the second, to get:
2y--y=-2-2
This implies that:
2y+y=-2-2
Simplify to get:
3y=-4
Divide both sides by 3 to get:
We substitute y=-1.3 into the first equation to get:
x--1.3=2
x+1.3=2
x=2-1.3
x=0.7
The solution is (0.7,-1.3), which is approximately (0.7, -1.4)
By inspection, all the other factors have solutions not close to (0.7, -1.4)
Answer:
<h2>3.6°</h2>Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;
is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°