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Aneli [31]
3 years ago
14

16/12 as a mixed number and 1(5)/(8) as an improper fraction?

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0

Answer:

Step-by-step explanation:

\frac{16}{12}=1\frac{4}{12}\\\\1\frac{5}{8}=\frac{(1*8)+5}{8}=\frac{13}{8}

saw5 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

16/12 as a mised number  is 1 4/12 or 1 1/3

1 5/8 as an improper fraction is 13/8

hope this helps <3

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Answer:

Option c

-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

<em><u>Then we perform operation -7A </u></em>

-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)

<u><em>Now we perform operation -6B </em></u>

-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)

Now we add the resulting matrices

\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

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\frac{3-7}{2 - (-2)}

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Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
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