On the 40th and the 80th you will receive both a free beverage and a free appetizer. You can find this by simply finding the multiples of both number up to 100 (or a little more than 100) to find out on which dates you'd get bothe an appetizer and beverage for free. Here are the multiples of both, to prove this answer.
- 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104.
- 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.
Thus making 40 and 80 the answers. I hope this helps!
A:B = 2:3
A=126
B=?
126/2=63
63x3=189
A=126
B=189
A:B = 126:189
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Y - 2x ≤ -3y - 2x ≤ -3
y - 2x ≤ -3y - 2x
y + 3y - 2x + 2x ≤ 0
4y ≤ 0
y ≤ 0
-3y - 2x ≤ -3
-3(0) - 2x ≤ -3
-2x ≤ -3
x ≥ 3/2
One of the solutions to the inequality is (3/2, 0)