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3 years ago

The sum of 5 consecutive even numbers is 310. What is the third number in this sequence?

1 answer:

3 0

A simple way to solve for consecutive numbers is to divide the sum number by the number of numbers needed. So 310 ÷ 5, which equals 62. That is the middle consecutive number.

To find the other 4 numbers, since they are all even, sinply add 2 to the middle number to find one, add 2 to that to find another, subtract 2 from the middle number to fine the third, and subtract 2 from that to find the final one.

62 + 2 = 64
64 + 2 = 66
62 - 2 = 60
60 - 2 = 58

so your numbers are 58, 60, 62, 52, and 66. Together they add up to 310.

(I may have done this a non-standard way, bit it was the way that made the most sense in my head.)

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A well-mixed cookie dough will produce cookies with a mean of 6 chocolate chips apiece. What is the probability of getting a coo

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The probability of getting a cookie with no more than 3 chips is 0.714.

<h3>What is probability?</h3>

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

Well-mixed cookie dough will produce cookies with a mean of 6 chocolate chips apiece.

Using poison ratio:

$\rm P (X = k) = \dfrac{\lambda^k e^{-\lambda}}{k!}$

λ is the mean number of chocolate chips in a piece

$\rm P (X = 6) = \dfrac{6^k e^{-6}}{k!}$

P(X ≥ 5) = 1 - P(X < 5)

P(X ≥ 5) = 1 - P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

$\rm P(X \geq 5) = 1-[\dfrac{6^0 e^{-6}}{0!}+\dfrac{6^1 e^{-6}}{1!}+\dfrac{6^2 e^{-6}}{2!}+\dfrac{6^3 e^{-6}}{3!}+\dfrac{6^4 e^{-6}}{4!}]$

After solving;

P(X ≥ 5) = 0.714

Thus, the probability of getting a cookie with no more than 3 chips is 0.714.

Learn more about the probability here:

brainly.com/question/11234923

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