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PolarNik [594]
3 years ago
6

Let ƒ(x) = x^2 + 2x and g(x) = 2x. Evaluate the composition (ƒ ∘ g)(2).

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:

The answer is option D.

Step-by-step explanation:

f(x) = x² + 2x

g(x) = 2x

To find (ƒ ∘ g)(2) first find (ƒ ∘ g)

To find (ƒ ∘ g) wherever you see x in f(x) replace it with g(x)

That's

(ƒ ∘ g) = (2x)² + 2(2x)

= 4x² + 4x

Substitute 2 into the expression

That's

(ƒ ∘ g)(2) = 4(2)² + 4(2)

= 4(4) + 8

= 16 + 8

= 24

Hope this helps you.

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DiKsa [7]

Firstly let's find hypotenuse(let it will be "n" of smaller triangle

Let use Pythagorean theorem

a^{2}  +  {b}^{2}  =  {n}^{2}  \\  {20}^{2}  +  {10}^{2}  =  {n}^{2}  \\  n =  \sqrt{500}

Now we need to find hypotenuse(x) of bigger triangle

{c}^{2}  +  {n}^{2}  =  {x}^{2}  \\  {9}^{2}  +  { \sqrt{500} }^{2}  =  {x}^{2}  \\ x =  \sqrt{581}

The value of x must be rounded to 1 DP, so

\sqrt{581}  = 24.1039... \\  \sqrt{581}  \simeq \: 24.1

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3 years ago
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Answer:

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2x+3=5x-2

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B-4%7D%20%7D%7B%283%2B1%29-%282%2B3i%29%7D%20" id="TexFormula1" title
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