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Murrr4er [49]
3 years ago
8

Find a value of x that is a solution to 5(x – 3) = x + 13.

Mathematics
2 answers:
svet-max [94.6K]3 years ago
7 0

Answer:

x=7

Step-by-step explanation:

5(x-3)=x+13\\5x-15=x+13\\Subtract x from both sides \\4x-15=13\\Add 15 to both sides\\4x= 28\\Divide both sides by 4\\x=7

Now check your answer

5(7-3)=7+13\\35-15=20\\20=20

bezimeni [28]3 years ago
3 0

Answer:

x = 7

Step-by-step explanation:

5(x-3)=x+13

distribute

5x-15= x+13

combine like terms

5x-x = 13 + 15

4x=28

x = 7

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Y''+Y'+Y=1<br> solve ordinary differential equation
taurus [48]

Answer:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

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y" + y' + y = 1

This is a second order nonhomogenous differential equation with constant coefficients.

First, find the roots of the complementary solution.

y" + y' + y = 0

r² + r + 1 = 0

r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)

r = [ -1 ± √(1 − 4) ] / 2

r = -1/2 ± i√3/2

These roots are complex, so the complementary solution is:

y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)

Next, assume the particular solution has the form of the right hand side of the differential equation.  In this case, a constant.

y = c

Plug this into the differential equation and use undetermined coefficients to solve:

y" + y' + y = 1

0 + 0 + c = 1

c = 1

So the total solution is:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

To solve for c₁ and c₂, you need to be given initial conditions.

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3 years ago
Which is the value of 3b 2 - b when b=5 ??
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It should be 30 because the problem would teun into 3(5)2. 3(5)=15. (15)2=30

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