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2 years ago

Brainliest if correct

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

6 0

$\huge\fbox{Answer ☘}$

$4(2w + 2) - 11 \\ \\ = > 8w + 8 - 11 \\ \\ = > 8w - 3$

hope helpful~

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In the triangle ABC , Angle A = 46° and Angle B = 83°. How large is the exterior angle at C?

lisabon 2012 [21]

Answer:

180 - 46 - 83 = 51 is the measure of angle C

the exterior angle at angle C, and angle C, are supplementary. since angle C is 51 because of the interior angle triangle sum theorem, then the exterior angle is: 180 -51 = 129 degrees.

Step-by-step explanation:

I hope this helps :)

4 0

3 years ago

Mr. West is standing on a cliff that is 25 1/5meters above the surface of the ocean. He spots a dolphin that is 2 3/5 meters und

zhenek [66]

Answer:

Total distance from Mr. West to dolphin $=27\frac{4}{5}\ meters$

Step-by-step explanation:

Height of cliff on which Mr. West is standing above the surface of ocean = $25 \frac{1}{5} \ meters$

Mr. West spot the dolphin under the water at a depth of = $2\frac{3}{5} \ meters$

∴ Total distance from Mr. West to dolphin= $(25 \frac{1}{5}+2\frac{3}{5})\ meters$

Adding mixed numbers

$(25 \frac{1}{5}+2\frac{3}{5})$

Adding whole numbers first.

$=25+2+\frac{1}{5}+\frac{3}{5}\\=27+\frac{1}{5}+\frac{3}{5}$

Adding fractions by taking LCD.

$=27+\frac{1+3}{5}\\=27+\frac{4}{5}\\=27\frac{4}{5}\ meters$

5 0

3 years ago

A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0

3 years ago

I need to help to solve this with answer?

Alinara [238K]

Answer:

137°

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Put in least to highest order 6.86,6.8,7,6.9,6.827 and 12.03,1.2,12.3,1.203,12.301

Anon25 [30]