3 years ago

I got (x+1)/(x^2+2x)

Mathematics

1 answer:

IrinaVladis [17]3 years ago

6 0

Answer:

Step-by-step explanation:

(x²-x-6)/(2x²-6x)•(x²+x)/(x²+4x+4)

[(x-3)(x+2)]/[2x(x-3)]•[x(x+1)]/[(x+2)(x+2)]

(x-3)/(x-3)•(x+2)/(x+2)•x/(2x)•(x+1)/(x+2)

1/2•(x+1)/(x+2)

(x+1)/(2x+4)

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4 years ago

I got (x+1)/(x^2+2x)​

I got (x+1)/(x^2+2x)