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8_murik_8 [283]
4 years ago
8

What does it mean when a question number is circled in a textbook

Mathematics
1 answer:
RoseWind [281]4 years ago
5 0
This is only my opinion.  I could be wrong.

My guess is:

Somebody else used that book before you, maybe last year or
the year before, and it was somebody who didn't mind writing
in his book.

One day he didn't have time to write down the homework in his
assignment notebook, so he just circled the homework problems
in his textbook.

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The solutions of x^2= 16x-28
STALIN [3.7K]

Answer:

Simplifying

x2 = 16x + -28

Reorder the terms:

x2 = -28 + 16x

Solving

x2 = -28 + 16x

Solving for variable 'x'.

Reorder the terms:

28 + -16x + x2 = -28 + 16x + 28 + -16x

Reorder the terms:

28 + -16x + x2 = -28 + 28 + 16x + -16x

Combine like terms: -28 + 28 = 0

28 + -16x + x2 = 0 + 16x + -16x

28 + -16x + x2 = 16x + -16x

Combine like terms: 16x + -16x = 0

28 + -16x + x2 = 0

Factor a trinomial.

(2 + -1x)(14 + -1x) = 0

Subproblem 1

Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying

2 + -1x = 0

Solving

2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.

2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0

0 + -1x = 0 + -2

-1x = 0 + -2

Combine like terms: 0 + -2 = -2

-1x = -2

Divide each side by '-1'.

x = 2

Simplifying

x = 2

Subproblem 2

Set the factor '(14 + -1x)' equal to zero and attempt to solve:

Simplifying

14 + -1x = 0

Solving

14 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-14' to each side of the equation.

14 + -14 + -1x = 0 + -14

Combine like terms: 14 + -14 = 0

0 + -1x = 0 + -14

-1x = 0 + -14

Combine like terms: 0 + -14 = -14

-1x = -14

Divide each side by '-1'.

x = 14

Simplifying

x = 14

Solution

x = {2, 14}

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Solve the formula for the specified variable.<br><br> V=AQT for A
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Answer:

A = \frac{V}{QT}

Step-by-step explanation:

To solve the problem you want to have A on one side, everything else on the other side. You can move over the variables by divind them from each side as shown:

AQT = V

AQT = \frac{V}{1}

AQ = \frac{V}{T}

A = \frac{V}{QT}

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