Answer: 0.345
Step-by-step explanation:
Given : The incomes of families in Newport Harbor are normally distributed with Mean :
and Standard deviation : 
Samples size : n=4
Let x be the random variable that represents the incomes of families in Newport Harbor.
The z-statistic :-

For x= $800,000

By using the standard normal distribution table , we have
The probability that the average income of these 4 families exceeds $800,000 :-

Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345
Answer is
0.8(2x-6)
Step-by-step explanation:
0.8x2x=1.6x
0.8x-6 = -4.8
Answer:
$2,323.2
Step-by-step explanation:
A = P(1 + r/n)^nt
Where,
A = future value = ?
P = present value = 2,000
r = interest rate = 5% = 0.05
n = number of periods = 12
t = time = 3 years
A = P(1 + r/n)^nt
= 2,000(1 + 0.05/12)^12*3
= 2,000( 1 + 0.00417)^36
= 2,000( 1.00417)^36
= 2,000(1.1616)
= 2,323.2
A = $2,323.2
Answer:
1/4x
Step-by-step explanation:
1/4x is a linear equation because it has a constant slope, and the slope of a line is shown before the x.
Each would be 20 cents.
So why did he change his mind about the apples?