Answer:
None of the above.
Step-by-step explanation:Yes, all of the sides match, which would make it an equilateral polygon. However, it is not an equiangular polygon because not all of the angels are the same. In this case, since the angles do not mach and only the sides do, this is not a regular polygon. This is what leads me to believe that is none of them. All of the sides must be congruent and all interior angles must also be congruent.
OK first convert one of the equations into Y=MX+b form
Y-2x = 3
Add 2X
Y = 2x +3
Now substitute this equation in the other one.
So it would be
3X - 2Y = 5
3X-2(2x+3) = 5
Now solve for y
3X - 4X - 6 = 5
-1X - 6 = 5
Add 6
-1X = 11
X = -11
Now substitute this into one of the equations
Y - 2X = 3
Y -2(-11) = 3
Y +22 = 3
y = 3-22
y = -19
Answer:
graph g(x)=1/4 x^2 - 2
Step-by-step explanation:
You are to replace x with (1/2x) in the expression x^2-2
So you have (1/2x)^2-2
1/4 x^2-2
Graph some points for g(x)=1/4 x^2-2
The vertex is (0,-2) and the parabola is open up.
I would graph 2 more points besides the vertex
x | g(x) ordered pairs to graph
----------- (-1,-1.75) and (0,-2) and (1,-1.75)
-1 -1.75
0 -2
1 -1.75
Hello,
Answer B: false
the parallelogram is a rectangle
Answer:
1 solution
Step-by-step explanation:
