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ioda
3 years ago
9

Can i have some help

Mathematics
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

you can ask questions that are on tests or live exams. I have reported this to brainly. Please don't do that again.

Step-by-step explanation:

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Please help with steps as well!!
satela [25.4K]

Answer:x=24

Step-by-step explanation:x/2-8=4

Add 8 to both sides

x/2=12

Multiply each side by 2

x=24



3 0
3 years ago
Read 2 more answers
Help hell help help gelp help
IgorC [24]
Just read what it says not that hard go to the left twice and go up 4 units.

Hope you have a good day
3 0
3 years ago
How do I make 3 - 10= 7 into an integer
Delicious77 [7]
All you have to do is subtract 10 from 3, which equals -7, and there you have an integer
8 0
3 years ago
If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

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3 years ago
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