If −5e^x^2 y=x and y(−5)=0, find y′(−5) by implicit differentiation

1 answer:

xenn [34]3 years ago

6 0

Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5

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