4.3-4.4 section of pre-calculus problem in link please also tell how you got your answer if can .

Dominic considers buying 2 points on a 25-year, fixed rate mortgage for $187,600. His interest rate will be 5.45% if he does not

algol [13]

Answer:

If Dominic buys 2 points (2% of the loan value) he will get a better rate and hence less payment. The question is asking how long will it take him to save the initial investment of 2% of the loan value due to a smaller payment. The monthly payment at 5.45% is $1,146.43, the monthly payment for 5.2% is $1,118.66. This is a difference of $27.77 per month. The 2 points will cost him $3,752.00. The question is asking how long will it take Dominic to re-coup his $3,752.00 if he saves $27.77 per month. Just divide the 2 numbers and you get 135.10 months. If you divide that by 12 you get 11.26 years, which is roughly 11 years, 4 months.

Step-by-step explanation:

Here is what the question is asking. If Dominic buys 2 points (2% of the loan value) he will get a better rate and hence less payment. The question is asking how long will it take him to save the initial investment of 2% of the loan value due to a smaller payment. The monthly payment at 5.45% is $1,146.43, the monthly payment for 5.2% is $1,118.66. This is a difference of $27.77 per month. The 2 points will cost him $3,752.00. The question is asking how long will it take Dominic to re-coup his $3,752.00 if he saves $27.77 per month. Just divide the 2 numbers and you get 135.10 months. If you divide that by 12 you get 11.26 years, which is roughly 11 years, 4 months.

3 0

2 years ago

Combine and simplify the following radical expression ASAP ASAP ASAP ASAP

Montano1993 [528]

Answer:

$\sqrt[3]{3}$

Step-by-step explanation:

Our expression is: $\frac{1}{3} \sqrt[3]{81}$ .

Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or $3^3*3$ . Put this in for 81:

$\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}$

We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:

$\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}$