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3 years ago

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4.3-4.4 section of pre-calculus problem in link please also tell how you got your answer if can .

1 answer:

Tanya [424]3 years ago

7 0

Answer:

the image os not clear mate sorry

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Bill and Joe leave their house at the same time heading in opposite directions. If Bill is driving three times faster than Joe a

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The problem statement gives you the relationship between their speeds, and it gives you information you can use to find their total speed. You solve this by finding the total speed, then the proportion of that belonging to Bill.

The total speed is (120 mi)/(3 h) = 40 mi/h.

The speed ratio is ...

... Bill : Joe = 3 : 1

so the speed ratio Bill : Total is ...

... 3 : (3+1) = 3:4.

Bill's speed is (3/4)×(40 mi/h) = 30 mi/h.

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4 years ago

Pleas help me for 20 points

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Answer:

240

Step-by-step explanation:

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3 years ago

Please help me with this quadratic equation question! I always give out 5 stars, thanks and brainliest to people that help me wi

ss7ja [257]

Answer:

$p=25,\\q=12$

Step-by-step explanation:

In $(ax+b)(cx+d)=acx^2+bcx+dax+bd$ , notice the third term of the quadratic in standard form is formed entirely by $b\cdot d$ .

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3 years ago

A bag contains 42 cups of dog food. Your dog eats 2 1/3 cups of dog food 1 point

Strike441 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval

Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

$\alpha = 1-99$ %

$=1-0.99$

$=0.01$

then,

$\frac{\alpha}{2} =\frac{0.01}{2}$

$=0.005$

or,

$Z_{\frac{\alpha}{2} }=Z_{0.005}$

$=2.576$

Now,

The point estimate will be:

⇒ $\hat{P}=\frac{x}{n}$

⇒ $=\frac{110}{343}$

⇒ $=0.321$

or,

⇒ $1-\hat{P}=1-0.321$

⇒ $=0.679$

The margin of error will be:

⇒ $E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )$

On substituting the above values, we get

⇒ $=2.576\times \sqrt{\frac{0.321\times 0.679}{343} }$

⇒ $=2.576\times \sqrt{\frac{0.217959}{343} }$

⇒ $=0.065$

hence,

⇒ $\hat{P}-E$

⇒ $0.321-0.065$

⇒ $0.256,0.386$

6 0

3 years ago