4.3-4.4 section of pre-calculus problem in link please also tell how you got your answer if can .

Which of the following equations have no solutions? Choose all answers that apply:

Marianna [84]

Answer:

All

Step-by-step explanation:

3 0

1 year ago

What equation represents the graphed function

Marina86 [1]

Answer: $y=\dfrac{-1}{3}x+3$

Step-by-step explanation:

The equation of ab line that passes through two points (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-c}{b-a}(x-a)$

From the given picture , the line is passing through points (0,3) and (3,2).

Then, the equation of the line will be :-

$(y-3)=\dfrac{2-3}{3-0}(x-0)$

$\Rightarrow y-3=\dfrac{-1}{3}x$

$\Rightarrow y=\dfrac{-1}{3}x+3$

Hence, the required equation of the line that represents the graphed function : $y=\dfrac{-1}{3}x+3$

7 0

3 years ago

Read 2 more answers

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a

kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented $h(t)=-16t^2+20t$ .

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?

We will use average rate of change formula to solve our given problem.

$\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}$

$\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{6}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{2\cdot 6}{1}$

$\text{Average rate of change}=12$

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0

2 years ago

Which answers are equal to the expression below? Check all that apply PLEASE WILL GIVE BRAINLIEST

kramer

Answer:

B., D., E.

Step-by-step explanation:

$\sqrt{9} \cdot \sqrt{100} =$

$= \sqrt{9 \cdot 100}$ This is choice B.

$= \sqrt{900}$ This is choice E.

$= 30$ This is choice D.

5 0

2 years ago

Divide -3x^3-2x^2-x-2 by x-2

Rasek [7]

Let's do this by Briot-Ruffini

First: Find the monomial root

x - 2 = 0

x = 2

Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2

Copy the first coeficient

2 | -3 -2 -1 -2

-3

Multiply him by the root and sum with the next coeficient

2.(-3) = -6

-6 + (-2) = -8

2 | -3 -2 -1 -2

-3 -8

Do the same

2.(-8) = -16

-16 + (-1) = -17

2 | -3 -2 -1 -2

-3 -8 -17

The same,

2.(-17) = -34

-34 + (-2) = -36

2 | -3 -2 -1 -2

-3 -8 -17 -36

Now you just need to put the "x" after all these numbers with one exponent less, see

2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36

You may be asking what exponent -36 should be, and I say:

None or the monomial. He's like the rest of this division, so you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)

Just divide the rest by the monomial.

5 0

2 years ago