Answer:

The net in the attached figure
Step-by-step explanation:
we know that
The surface area of the square pyramid using a net, is equal to the area of a square plus the area of its four lateral triangular faces
so
![SA=16^2+4[\frac{1}{2}(16)(13)]](https://tex.z-dn.net/?f=SA%3D16%5E2%2B4%5B%5Cfrac%7B1%7D%7B2%7D%2816%29%2813%29%5D)

Answer:
Apprentice=$800
Journeyman=$1600
Master=$2400
Step-by-step explanation:
We have that all the crew won a total of $4800 then it is the salary of the apprentice, the journeyman and the master carpenter. It say that the journeyman makes 200% of the apprentice, then it means that the journeyman won the double of the apprentice. The master won 150% of what a journeyman, it means that the master won 1.5 of the salary of the journeyman.
With this information we can write the next set of equations.

Using the second equation in the third equation we can know how much won the master in terms of the salary of the apprentice, then:

With this we could rewrite the first equation as:

Then the aprentice earn $800, the journeyman $1600 and the master $2400
The test statistic and p-value of the given data are 6.274 and 0.0001 respectively.
<h3>Test Statistic</h3>
The test statistic can be calculated using the formula below

Solving for the mean and standard deviation, we can substitute the values into the above equation which will be

<h3>P-Value</h3>
Using the data from the test statistic, we can calculate the p-value of the data

From the calculation above, the test statistic and p-value of the given data are
Learn more on test statistic and p-value here;
brainly.com/question/4621112
1)
here, we do the left-hand-side
![\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2 \\\\\\\ [sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)] \\\\\\ 2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2](https://tex.z-dn.net/?f=%5Cbf%20%5Bsin%28x%29%2Bcos%28x%29%5D%5E2%2B%5Bsin%28x%29-cos%28x%29%5D%5E2%3D2%0A%5C%5C%5C%5C%5C%5C%5C%0A%5Bsin%5E2%28x%29%2B2sin%28x%29cos%28x%29%2Bcos%5E2%28x%29%5D%5C%5C%5C%5C%2B~%20%5Bsin%5E2%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E2%28x%29%5D%0A%5C%5C%5C%5C%5C%5C%0A2sin%5E2%28x%29%2B2cos%5E2%28x%29%5Cimplies%202%5Bsin%5E2%28x%29%2Bcos%5E2%28x%29%5D%5Cimplies%202%5B1%5D%5Cimplies%202)
2)
here we also do the left-hand-side
![\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x) \\\\\\ \cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)} \\\\\\ \cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B2-cos%5E2%28x%29%7D%7Bsin%28x%29%7D%3Dcsc%28x%29%2Bsin%28x%29%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B2-%5B1-sin%5E2%28x%29%5D%7D%7Bsin%28x%29%7D%5Cimplies%20%5Ccfrac%7B2-1%2Bsin%5E2%28x%29%7D%7Bsin%28x%29%7D%5Cimplies%20%5Ccfrac%7B1%2Bsin%5E2%28x%29%7D%7Bsin%28x%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B1%7D%7Bsin%28x%29%7D%2B%5Ccfrac%7Bsin%5E2%28x%29%7D%7Bsin%28x%29%7D%5Cimplies%20csc%28x%29%2Bsin%28x%29)
3)
here, we do the right-hand-side
Im pretty sure it's 17.5 since 35 is odd.