To answer this question you have to determine how many feet are in a mile and multiply it by 70. There are 5280 feet in a mile, so 5280 x 70= 369600. So he can run 369600ft in an hour. (im pretty sure lol, i feel like i may have misunderstood this question, are there any answer choices?)
Answer:
20 tea bags
Step-by-step explanation:
if 5 is 1 gallon then you do 5x4=20
Answer:



The standard deviation will remain unchanged.
Step-by-step explanation:
Given

Solving (a): The range
This is calculated as:

Where:

So:


Solving (b): The variance
First, we calculate the mean




The variance is calculated as:

So, we have:
![\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B6-1%7D%2A%5B%28136%20-%20135%29%5E2%20%2B%28129%20-%20135%29%5E2%20%2B%28141%20-%20135%29%5E2%20%2B%28139%20-%20135%29%5E2%20%2B%28138%20-%20135%29%5E2%20%2B%28127%20-%20135%29%5E2%5D)
![\sigma^2 =\frac{1}{5}*[162]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B5%7D%2A%5B162%5D)

Solving (c): The standard deviation
This is calculated as:


--- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.
Given:
The scale factor is 1:12.
Dimension of model = 32 cm
To find:
The actual dimension in m.
Solution:
Let x be the actual dimension.
The scale factor is 1:12 and the dimension of model is 32 cm.

On cross multiplication, we get


![[\because 1\ m=100\ cm]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%5C%20m%3D100%5C%20cm%5D)
Therefore, the actual dimension is 3.84 m.