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AnnZ [28]
3 years ago
14

Can someone help me with this please thank you

Mathematics
1 answer:
o-na [289]3 years ago
8 0
For 19 it is number 2 that does not have x = 20.
for 20 its the last one that the variable does not equal 12.
the answer for 21 is 6.
and the answer for 22 is 72.
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Look at the images please help
Wittaler [7]

Answer:

SA=672\ yd^2

The net in the attached figure

Step-by-step explanation:

we know that

The surface area of the square pyramid using a net, is equal to the area of a square plus the area of its four lateral triangular faces

so

SA=16^2+4[\frac{1}{2}(16)(13)]

SA=256+416=672\ yd^2

6 0
3 years ago
A crew consists of 1​ apprentice, 1​ journeyman, and 1 master carpenter. The crew receives a check for ​$4800 for a job they jus
tamaranim1 [39]

Answer:

Apprentice=$800

Journeyman=$1600

Master=$2400

Step-by-step explanation:

We have that all the crew won a total of $4800 then it is the salary of the apprentice, the journeyman and the master carpenter. It say that the journeyman makes 200% of the apprentice, then it means that the journeyman won the double of the apprentice. The master won 150% of what a journeyman, it means that the master won 1.5 of the salary of the journeyman.

With this information we can write the next set of equations.

A+J+M=\$4800\\J=2A\\M=1.5J

Using the second equation in the third equation we can know how much won the master in terms of the salary of the apprentice, then:

M=1.5J\\M=1.5(2A)\\M=3A

With this we could rewrite the first equation as:

A+J+M=\$4800\\A+2A+3A=\$4800\\6A=\$4800\\A=\dfrac{\$4800}{6}\\A=\$800

Then the aprentice earn $800, the journeyman $1600 and the master $2400

6 0
3 years ago
Researchers gave 40 index cards to a waitress at an Italian restaurant in New Jersey. Before delivering the bill to each custome
rjkz [21]

The test statistic and p-value of the given data are 6.274 and 0.0001 respectively.

<h3>Test Statistic</h3>

The test statistic can be calculated using the formula below

t = \frac{x-\mu}{\sigma / \sqrt{n} }

Solving for the mean and standard deviation, we can substitute the values into the above equation which will be

t = \frac{x-\mu}{\sigma / \sqrt{n} } = 6.274

<h3>P-Value</h3>

Using the data from the test statistic, we can calculate the p-value of the data

p-value = p(z < 6.274)= 0.0001 = 0.00

From the calculation above, the test statistic and p-value of the given data are

  • 6.274
  • 0.0001

Learn more on test statistic and p-value here;

brainly.com/question/4621112

3 0
2 years ago
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2&#10;\\\\\\\&#10;[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]&#10;\\\\\\&#10;2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)&#10;\\\\\\&#10;\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}&#10;\\\\\\&#10;\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}&#10;\\\\\\&#10;\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}&#10;\\\\\\&#10;\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
8 0
3 years ago
If y varies directly with x, and y is 14 when x is 2, what is the value of x when y is 35?
Ainat [17]
Im pretty sure it's 17.5 since 35 is odd.
4 0
3 years ago
Read 2 more answers
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