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AnnZ [28]
2 years ago
14

Can someone help me with this please thank you

Mathematics
1 answer:
o-na [289]2 years ago
8 0
For 19 it is number 2 that does not have x = 20.
for 20 its the last one that the variable does not equal 12.
the answer for 21 is 6.
and the answer for 22 is 72.
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May you please help me. Do not Skip this Question. URGENT!
iren [92.7K]

Answer:

C

Step-by-step explanation:

The common ratio can be < 0

All that means is the entry's signs alternate.

For example

r = - 2

a = 3

Series = 3    -6    18     -54 etc. The members of the series become larger and larger in magnitude and the series diverges. It is not clear where it might stop.

-1 < r < 0 gives a much better behaved result.

The point is that c is incorrect.

3 0
3 years ago
Given the equation (x-a)^2(x-2)=x^3+bx^2+12x-72 find a and b
ivann1987 [24]
Isolate the variable by dividing each side by factors that don't contain the variable.

a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variable.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!
 


3 0
3 years ago
HELP ASAP FOR BRAINLIEST
natka813 [3]

Answer:

119 degrees

Step-by-step explanation:

The measure of EAC is 119 because 62 + 57 = 119.

Then, EAC and BAD are vertical angles, so they are equal.

Therefore, BAD = 119 degrees

4 0
2 years ago
Read 2 more answers
Help?!!?? I don’t get it??
solong [7]

Answer:

1/6

Step-by-step explanation:

1/2 (The probability that its tails) x 1/3(The probability that it lands on a green side)

8 0
3 years ago
There are 25 students that would like to go on a field trip, but only 18 may go. How many different combinations of students cou
Naya [18.7K]

480700. The different combinations of students that could go on the trip with a total of 25 student, but only 18 may go, is 480700.

The key to solve this problem is using the combination formula nC_{r}=\frac{n!}{r!(n-r)!}. This mean the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.

The total of students is n and the only that 18 students may go is r:

25C_{18}=\frac{25!}{18!(7!)}=480700

6 0
3 years ago
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