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Orlov [11]
2 years ago
13

What's the answer?can you help me with this

Mathematics
1 answer:
anzhelika [568]2 years ago
4 0
A = 1/2 bh

A = 1/2 • (6x + 4)(x-7)

Use FOIL to multiply the binomials

A = 1/2 • 6x^2 - 3x - 28

Multiply the (1/2) in

A = 3x^2 - 3/2x - 14

Final answer!
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Roger ran eight laps around a mile track during PE on Monday. Answer each question in the space provided. Part A How many feet d
Gre4nikov [31]

Answer:

A) 10,560 ft. B) 32 more laps.

Step-by-step explanation:

A) Four laps around a track is equal to one mile, and there are 5,280 feet in one mile. If Roger ran eight laps, he ran two miles. Therefore: 5,280 ft. times 2, is equal to 10,560 ft.

B) We know that Roger ran two miles Monday. We also know that four laps around a track is equal to one mile. In order to run 10 miles, he would have to run 40 laps, and since he already ran 8, we can subtract that from 40. You are left with 32 more laps.

5 0
3 years ago
Every day Amy travels 30 miles one-way to work. The park-and-ride where she catches the train is 5 miles from her home. The aver
sukhopar [10]

Answer:

26

Step-by-step explanation:

3 0
3 years ago
.......... is the slope zero
Eddi Din [679]

Answer:


Step-by-step explanation:

OK... You have to use this formula: <u>Y2 - Y1</u>

                                                          X2 - X1

  • -2 represents X1
  • 7 represents Y1
  • 2 represents X2
  • -5 represents Y2    

<u>Y2 - Y1</u>

X2 - X1

<u>-5 - 7</u>

2 - - 2

<u>-12</u>

-2

Simplify by dividing both -12 & -2 by 2: <u>-6</u>

                                                                 -1

It's either <u>-6</u> or it's just -6 by itself... Really sorry if I'm wrong...

                -1  




4 0
3 years ago
Read 2 more answers
Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.
Levart [38]

Answer:

The standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

7 0
2 years ago
Brainliest if correct
natali 33 [55]

\left(15^{1/5} \right)^5  = 15^{(5/5)} = 15^1 = 15

6 0
2 years ago
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