Now I’m ngl my math might be wrong but I ended up with 1131/48
As a decimal I got 23.6
Let the number of apples be x and that of pears be y, then:
0.64x + 0.45y = 5.26 . . . (1)
0.32x + 0.39y = 3.62 . . . (2)
(2) x 2 => 0.64x + 0.78y = 7.24 . . . (3)
(1) - (3) => -0.33y = -1.98
y = -1.98 / -0.33 = 6
From (2), 0.32x + 0.39(6) = 3.62
0.32x = 3.62 - 2.34 = 1.28
x = 1.28 / 0.32 = 4
Therefore, he bought 4 apples and 6 pears.
The simulation of the medicine and the bowler hat are illustrations of probability
- The probability that the medicine is effective on at least two is 0.767
- The probability that the medicine is effective on none is 0
- The probability that the bowler hits a headpin 4 out of 5 times is 0.3281
<h3>The probability that the medicine is effective on at least two</h3>
From the question,
- Numbers 1 to 7 represents the medicine being effective
- 0, 8 and 9 represents the medicine not being effective
From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two
So, the probability is:
p = 23/30
p = 0.767
Hence, the probability that the medicine is effective on at least two is 0.767
<h3>The probability that the medicine is effective on none</h3>
From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none
So, the probability is:
p = 0/30
p = 0
Hence, the probability that the medicine is effective on none is 0
<h3>The probability a bowler hits a headpin</h3>
The probability of hitting a headpin is:
p = 90%
The probability a bowler hits a headpin 4 out of 5 times is:
P(x) = nCx * p^x * (1 - p)^(n - x)
So, we have:
P(4) = 5C4 * (90%)^4 * (1 - 90%)^1
P(4) = 0.3281
Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281
Read more about probabilities at:
brainly.com/question/25870256
Answer:
x = 7 , y= - 6
Step-by-step explanation:
4x = -2 - 5y ___(1)
4x= 10 - 3y ___(2)
so, now by simultaneous equations,
10 - 3y = - 2 - 5y
2y = -12
y = -6
if y = -6
then, 4x= 10 -3(-6)
4x =28
x = 7
