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3 years ago

How do you find the equation of a parabola given two x intercepts

1 answer:

4 0

Let's assume that the parabola has the following intersections with the x axis:
x1 = p
x2 = q
To find the equation of the parabola, we write the following product of binomials:
(x-p) (x-q) = 0
Where,
p, q: intersections with the x axis.
When developing the product of binomials, we obtain the equation of the parabola.
Answer:
(x-p) (x-q) = 0

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8 0

3 years ago

What value has a z-score of -0.67, if the mean is 18 and the standard deviation is 1.68?

uranmaximum [27]

The data point is 1.6 standard deviations above the mean.
Step-by-step explanation:
Z-score
It is the number of standard deviations from the mean that a data point is. It's a measure of how many standard deviations below or above the population mean a raw score is.
A Z-score is also known as a standard score and it can be placed on a normal distribution curve.
As in this case the Z-score is +1.6, so it means the data point is 1.6 standard deviations above the mean. Hope this helps I am kinda knew to this so I hope I helped you

7 0

3 years ago

HELP PLS ASAP I NEED HELP PLS HELP ANSWER THE QEUSTION IN THE PHOTO PLS

Stolb23 [73]

I am guessing it is b! because BG and BA are sides, and BAU and BGN are angles.

5 0

3 years ago

A store owner buys a sweater at $12 and sells it for $15. What was the

Colt1911 [192]

Answer:

it would be a 25% increase.

Step-by-step explanation:

15-12 / 12 * 100 =

3/12 * 100 = 25

3 0

3 years ago

Please help please these are short answers

atroni [7]

Answer: The answers are given below.

Step-by-step explanation: The calculations are as follows:

(19) Weight of the puppy last week is

$W_\ell=2\dfrac{1}{2}~\textup{lb},$

and weight of the puppy this week is

$W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.$

Therefore, the weight gained by the puppy is given by

$W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.$

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

$H_\ell=\dfrac{4}{9}~\textup{hr},$

and the time taken by Nazia to complete her Mathematics homework is

$H_m=\dfrac{2}{9}~\textup{hr}.$

Therefore, Nazia takes more time to complete Language Arts homework, by

$H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.$

(22) Quantity of Aluminium collected by Maya is

$A_m=\dfrac{4}{20}=0.2~\textup{lb},$

and the quantity of Aluminium collected by her friend Abigail is

$A_a=\dfrac{7}{8}=0.87~\textup{lb}.$

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

$T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.$

(23) Quantity of snow fall last Wednesday is

$S_w=3\dfrac{1}{4}=3.25~\textup{in.},$

and quantity of snowfall on sunday is

$S_s=3\dfrac{4}{5}=3.8~\textup{in.}.$

Therefore, quantity of snowfall was more on Sunday by

$S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.$

Thus, all the questions are answered.

3 0

3 years ago