Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
Old scale : 1 in. to 3 ft.
length is 9 in.....9 * 3 = 27 ft (old scale length)
width is 6 in......6 * 3 = 18 ft (old scale width)
new scale : 1 in. to 4 ft
length is 9 in.....9 * 4 = 36 ft (new scale length)
width is 6 in......6 * 4 = 24 ft (new scale width)
The answer is 281.01
good luck
Point S represents the ordered pair.
Answer:
60 degrees
Step-by-step explanation:
180-90=90
90-30=60
