Answer:
y = x + 1
Step-by-step explanation:
The gradient of a line can be defined by the equation:
m (gradient) = (y1 – y2 ) ÷ (x1 – x2) ----> "1" and "2" should be in subscript
For (-7,-6) we use x2 and y2 (because this point can be anywhere along a line):
x2 = -7, y2 = -6
Plug these values into the formula above:
m = (y-(-6)) ÷ (x-(-7))
m = (y+6) ÷ (x+7)
At this stage, the equation can't be solved as there are two unknowns. Therefore, the gradient must be found another way. Two lines are parallel if they have the same gradient - in their y=mx+c equations, m will be equal.
x - y=7 is the line alluded to in the question. Rearranging this equation into the line equation format gives:
y = x-7 ---> The gradient (coefficient of x) is 1.
Therefore, the gradient of the other parallel line must also be 1.
This can be substituted into the previous equation to give:
1 = (y+6)÷(x+7)
x+7 = y+6
x+1 = y
Therefore, the answer is y=x+1
Answer: B, Each of the sums is 180 degrees.
Step-by-step explanation:
Since a 180 degree angle is always a flat line, and that is the case for this,
Each of the sums is 180 degrees.
From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt(2).
So hypotenuse H = xSqrt(2), x=H/Sqrt(2).
Using numbers, if H = 7, then x = 7/Sqrt(2) = 7Sqrt(2)/2 to rationalize it.
Answer:
4 cm
Step-by-step explanation:
Both the area of a square and the area of a rectangle can be found by multiplying length x width. Because all of the sides of a square are equal, you get 64 when you multiply two sides together to find the area.
Since the rectangle has the same area as the square, that means the rectangle's width has to be a number that equals 64 when multiplied by 16.
So, 64/16 equals 4.
Please mark as brainliest ;)
In this question , we have to find, which option represents inverse functions.
Let's check out option b
Let it be y
So we have
Switching x and y and solving for y,
Performing cross multiplication
Combining like terms
Which is same as of the other function.
So correct option is b .
