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3 years ago

What's the ratio of 60 and 96

Mathematics

1 answer:

ella [17]3 years ago

3 0

$60:96$
$\frac{60}{12}:\frac{96}{12}$
5:8

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8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.

According to that, if $a + b = 0$ , then $a = 0$ and $b = 0$ .

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3 years ago

What is the condition of loss ?1)sp>mp 2)CP>sp 3) sp>CP 4)mp>sp

victus00 [196]

Step-by-step explanation:

what is the condition of loss ?1)sp>mp 2)CP>sp 3) sp>CP 4)mp>sp

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2 years ago

A teacher has 40 learners in her class. She chooses 1% to clean her board. Is this possible?

worty [1.4K]

Step-by-step explanation:

No, 1% of 40 is the same as 40% of 1. Which is 0.025% You cant have 0.025% of a learner or a human so this isn't possible.

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3 years ago

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drek231 [11]

A, C, And D

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3 years ago

Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

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by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

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2 years ago