I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
Answer:
$25.10
Step-by-step explanation:
lunch=$7.52
dinner=$9.74
breakfast=$5.16
money left=$2.68
make total money he began with ‘x’
to find the total money he began with it will be
x-lunch+dinner+breakfast=money left
x-$7.52+$9.74+$5.16=$2.68
x-$22.42=$2.68
x=$2.68+$22.42
x=$25.10
Answer:
B! 
Step-by-step explanation:
Because 10 minus 5 (from the y column) is -5. And -5 - (-2) is +3. So you get -5 over 3 (). which is B!
Can you give me brainliest please?? :)
Answer:8600
Step-by-step explanation:
477
Answer:
z²^30
Step-by-step explanation:
This is it enjoy.
