first off, let's recall that a cube is just 6 squares stacked up to each other, like in the picture below. Since we know its volume, we can find how long each side is.
part A)
![\bf \textit{volume of a cube}\\\\V=x^3~~\begin{cases}x=side\\[-0.5em]\hrulefill\\V=64\end{cases}\implies 64=x^3\implies \sqrt[3]{64}=x\implies 4=x](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cube%7D%5C%5C%5C%5CV%3Dx%5E3~~%5Cbegin%7Bcases%7Dx%3Dside%5C%5C%5B-0.5em%5D%5Chrulefill%5C%5CV%3D64%5Cend%7Bcases%7D%5Cimplies%2064%3Dx%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B64%7D%3Dx%5Cimplies%204%3Dx%20)
part B)
they have a painting with an area of 12 ft², will the painting fit flat against a side? Well, it can only fit flat if the sides of the painting are the same length or smaller than the sides of the crate, we know the crate is a 4x4x4, so are the painting's sides 4 or less?
![\bf \textit{area of a square}\\\\A=s^2~~\begin{cases}s=side\\[-0.5em]\hrulefill\\A=12\end{cases}\implies 12=s^2\implies \sqrt{12}=s\implies \stackrel{yes}{3.464\approx s}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Barea%20of%20a%20square%7D%5C%5C%5C%5CA%3Ds%5E2~~%5Cbegin%7Bcases%7Ds%3Dside%5C%5C%5B-0.5em%5D%5Chrulefill%5C%5CA%3D12%5Cend%7Bcases%7D%5Cimplies%2012%3Ds%5E2%5Cimplies%20%5Csqrt%7B12%7D%3Ds%5Cimplies%20%5Cstackrel%7Byes%7D%7B3.464%5Capprox%20s%7D%20)
Answer:
21/10
Step-by-step explanation:
you"ll have to take my word for it
Answer:
121.5
Step-by-step explanation: so what u are supost to do is multiply the sides which will give you your answer of 121.5.
Answer:
Least Likely: Arrow lands on a section labeled with an odd number.
_____: Arrow lands on a section labeled with the number 1.
Most Likely: Arrow lands on a section labeled with a number less than 4.
Step-by-step explanation:
<u>The spinner:</u>
There are 8 sections, 4 labeled with the number 1, 2 labeled with the number 3, 1 labeled with the number 3, and 1 labeled with the number 4.
<u>Probabilities of the spinner:</u>
- Probability of landing on 1: 4/8 - 50%
- Probability of landing on 2: 1/8 - 12.5%
- Probability of landing on 3: 2/8 - 25%
- Probability of landing on 4: 1/8 - 12.5%
<u>The options:</u>
A - Arrow lands on a section labeled with an odd number.
B - Arrow lands on a section labeled with the number 1.
C - Arrow lands on a section labeled with a number less than 4.
- The least likely possibility out of the options would be B because, while a 50% chance sounds like a lot, it is the least of the three options.
- The mid possibility out of the options would be A. The odd numbers labeled on the spinner make up 75% of the whole. (1s and 3s - 50% + 25%)
- The most likely possibility out of the options is C because it accounts for every section except for the single section labeled with the number 4. (100% - 12.5%, 87.5%)
66 quarters and 28 dimes.
It took some time, but it is easy if you put it in an algebraic equation.
