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andreyandreev [35.5K]
3 years ago
7

If a scale factor is grater than 1, then your figure gets

Mathematics
2 answers:
blsea [12.9K]3 years ago
6 0

Answer:

multiplied

Step-by-step explanation:

jok3333 [9.3K]3 years ago
6 0

Answer:

If a scale factor is greater than 1, then your figure gets bigger.

Step-by-step explanation:

For scale factors, you are multiplying the scale factor to get the desired outcome. If the scale factor is greater than 1, you are multiplying by a whole number, which would be ≥ the original number. If the scale is 1, then it would be = too the original number. If the scale factor is a fraction, then the figure would be scaled down.

~

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What is 1/2÷8? thanks
shusha [124]

Answer: 1/16

0.0625

Step-by-step explanation:

6 0
3 years ago
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Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

8 0
3 years ago
How do you do this and what are the answers
scoray [572]
I can answer 1 to 4...
The area of a circle can be found by \pi r^{2}. Reminder: \pi = 3.14 (usually used when finding out the area of a circle)

1. 4^{2} = 16
\pi *16 or 3.14 * 16 = 50.24
50.24/4=12.56

2. 6^{2} = 36
\pi *36 or 3.14 * 36 = 113.04
113.04/10=11.304

(Not really sure if this is correct) 3. 2^{2}=4
\pi *4 or 3.14 * 4
12.56/2.66666667=11.70999999

4. 6^{2}=36
\pi *36= 113.04
113.04/6=18.84
5 0
3 years ago
I need help it's due tomorrow​
hoa [83]

5 and 4

3 and 6

hope this helps!

4 0
3 years ago
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Darpana solved the equation s = StartFraction a + b + c Over 3 EndFraction for a. Her steps are shown below: 1. Multiply by 3: s
Harman [31]

Answer:

Option (c) is correct.

Step-by-step explanation:

Given equation is :

s=\dfrac{a+b+c}{3}

The equation can be solved for a as follows :

Step 1.

Cross multiply the given equation

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Step 2.

Now subtract b on both sides

3s-b = a+b+c-b

3s-b = a+c

Step 3.

Subtract c on both sides

3s-b-c=a+c-c

⇒ a=3s-b-c

The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".

5 0
3 years ago
Read 2 more answers
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