Find the midpoint of diagonal AC of ABCD
1 answer:
Answer:
M= (1, 3)
Step-by-step explanation:
we have from the picture:
A = (-3,5)
C = (5, 1)
M = Midpoint
M =((x1+x2)/2), ((y1+y2)/2)
so we have:
x1= -3 y1 = 5
x2= 5 y2= 1
M= ((-3+5)/2) , ((5+1)/2)
M = ((2/2) , (6/2))
M= (1, 3)
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