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Ket [755]
3 years ago
6

Find the midpoint of diagonal AC of ABCD

Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

M= (1, 3)

Step-by-step explanation:

we have from the picture:

A = (-3,5)

C = (5, 1)

M = Midpoint

M =((x1+x2)/2), ((y1+y2)/2)

so we have:

x1= -3     y1 = 5

x2= 5     y2= 1

M= ((-3+5)/2) , ((5+1)/2)

M = ((2/2) , (6/2))

M= (1, 3)

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Select the postulate or theorem that you can use to conclude that the triangles are similar.
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Answer: SAS similarity postulate

Step-by-step explanation:

According to SAS postulate of similarity, two triangles are called similar if two sides in one triangle are in the same proportion to the corresponding sides in the other, and the included angle are congruent.

In triangles, QNR and MNP,

\frac{QN}{MN} = \frac{QM+MN}{MN} = \frac{10+8}{8} = \frac{18}{8} = \frac{9}{4}

\frac{NR}{NP} = \frac{NP+NR}{NP} = \frac{10+8}{8} = \frac{18}{8} = \frac{9}{4}

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⇒ Option first is correct.

8 0
3 years ago
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B y+8 = 2(x-4)

Step-by-step explanation:

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