13. Since, it is given that we have to prove ΔGDH≅ΔFEH by HL rule, thus From ΔGDH, ∠GDH=90° and GH is the hypotenuse and from ΔFEH, ∠HEF=90° and HF is the hypotenuse, thus in ΔGDH and ΔFEH,

∠GDH≅∠HEF=90°

GH≅FH,

Thus by HL the given triangles are congruent.

Option A is correct.

14. From the figure, it can be seen that both triangles have a right angle congruent and hypotenuse congruent, thus by HL rule, triangle scan be prove congruent.

Option A is correct.

15. It is given that BI is parallel to RD, thus using the alternate interior angle property, ∠B≅∠R.

Option C is correct.

16. It is given that BI is parallel to RD, and ∠BSI and ∠RSD form the vertically opposite angles, thus ∠BSI≅∠RSD by vertical angles are congruent.

Option A is correct.

17. Since Δ ABC is an isosceles triangle, thus two sides of the triangle are equal, therefore ∠A=∠B=3x+5, using the angle sum property in ΔABC, we have

3x+5+2x+3x+5=180°

⇒8x+10=180

⇒8x=170

⇒x=21.25

Thus, ∠B=3x+5=3(21.25)+5=63.75+5=68.75°

18. From ΔJKL and ΔDEF, we have

∠K=∠E (given)

∠L=∠F(given)

JL=DF

Thus, By AAS rule ΔJKL ≅ ΔDEF

As corresponding angles and corresponding sides are equal in these two triangles as compared to the other triangles.

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