Answer:

Step-by-step explanation:
This expression was kind of trial and error for me seeing as I'm not really good at logic, but this is pretty basic. There are three possible places the parentheses can be placed (assuming each pair holds 2 terms);
The answer to the first expression would be 45, which is not equal to 11.
The answer to the second expression would be 15, which is also not equal to 11.
The answer to the last expression is 11, so that is the correct answer.
Hope this helped :D
- Shay
Answer:
The value of the test statistic is 
Step-by-step explanation:
The formula for the test statistic is:

In which X is the statistic,
is the mean,
is the standard deviation and n is the number of observations.
In this problem, we have that:

So



The value of the test statistic is 
Since 8 students take both, that leaves only 4 students who take Algebra I alone.
Likewise since 8 students take both, that leaves 10 who only take Algebra 2
So out of the 60, twenty two are taking either Alg I Alg Ii or both.
That leaves 38 people who are not taking either.
b. 38
You can set this up using a 2 circle venn diagram. Just be sure to put the 8 who take both in first.
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
56 is you answer you need.