So 90^2+90^2=c^2
8100+8100=c^2
16200=c^2
C= ~127.28
A. x= 11/5
b. x= 6
c. x= -12/2
d. x= 6/5
yes it is reasonable that employment has a normal distribution for each gender
Answer:
First solve the equation:
6x^2 + 8x -28 = 2x^2 + 4
=> 6x^2 - 2x^2 + 8x - 28 -4 = 0 => 4x^2 + 8x - 32 = 0
Extract common factor 4:
=> 4[x^2 + 2x - 8] = 0
Now factor the polynomial:
4(x + 4) (x - 2) = 0
=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.
So the answer is the option B: 4(x + 4)(x - 2); {-4, 2}
HOPE THIS HELPS! :D
