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3 years ago

Write the standard form of the equation of the line with slope-3 passing through the point (-1,-6)

1 answer:

8 0

Y = mx + b
slope(m) = -3
(-1,-6)...x = -1 and y = -6
now we sub and find b, the y int
-6 = -3(-1) + b
-6 = 3 + b
-6 - 3 = b
-9 = b

y = -3x - 9...add 3x to both sides
3x + y = -9 <== standard form

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One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe

sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who disagree with the statement = $\frac{1812}{2625}$ = 0.69

n = sample of respondents = 2625

p = population proportion of people who disagree with statement

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ , $0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ ]

= [0.667 , 0.713]

Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

5 0

3 years ago

What fractions Equivalent to 1/2

guajiro [1.7K]

Answer:

2/4 3/6

Step-by-step explanation:

any fraction where the numerator is half of the Denominator

4 0

3 years ago

Write a cubic function whose graph goes through the points: (-5, 0) (1, 0) (2, -2) (4, 0)

Free_Kalibri [48]

Answer:

f(x) = $\frac{1}{7}(x+5)(x-1)(x-4)$

Step-by-step explanation:

Let the equation of the give cubic function is,

f(x) = p(x - a)(x - b)(x - c)

Here, a, b, c and d are the x-intercepts of the given graph.

Since, x-intercepts given in the graph are x = -5, 1 and 4,

Equation of the curve will be,

f(x) = p(x + 5)(x - 1)(x - 4)

Since, the graph of this function passes through (2, -2) also

-2 = p(2 + 5)(2 - 1)(2 - 4)

-2 = -p(14)

p = $\frac{2}{14}$

p = $\frac{1}{7}$

Therefore, equation will be,

f(x) = $\frac{1}{7}(x+5)(x-1)(x-4)$

5 0

3 years ago

7. Sapna travelled 48 km to meet her parents. She travelled the first 18 km by car and the remaining distance by train. Find the

Anton [14]

The fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

We know that fraction is an expression in mathematics used to denote the division of two whole numbers.

Given that the total distance = 48 km.

The distance Sapna traveled by car = 18 km.

So, the fraction is = distance traveled by car/total distance = 18/48 = 3/8

The distance Sapna traveled by train = 48 - 18 km = 30 km.

So, the fraction is = distance traveled by train/total distance = 30/48 = 5/8

Therefore the fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

Know more about fractions here -

brainly.com/question/10354322

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6 0

2 years ago

CAN YOU HELP IN MATH

atroni [7]

Answer:

See below

Step-by-step explanation:

Domain: set of x values

Range: set of y values

Function: no two x values are the same

Line 1:

Domain: {3, 4, 5}

Range: {1, 2, 3, 4}

Function: no since there are two points with x-coordinate 3

Line 2:

Domain: {-1, -2, 1, 2}

Range: {1, 3}

Function: yes since all x-coordinates are different

Line 3:

Domain: {-2, -1, 0, 1, 2}

Range: {0, 1, 4}

Function: yes since all x-coordinates are different

8 0

2 years ago