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Sonbull [250]
2 years ago
5

CAN YOU HELP IN MATH​

Mathematics
1 answer:
atroni [7]2 years ago
8 0

Answer:

See below

Step-by-step explanation:

Domain: set of x values

Range: set of y values

Function: no two x values are the same

Line 1:

Domain: {3, 4, 5}

Range: {1, 2, 3, 4}

Function: no since there are two points with x-coordinate 3

Line 2:

Domain: {-1, -2, 1, 2}

Range: {1, 3}

Function: yes since all x-coordinates are different

Line 3:

Domain: {-2, -1, 0, 1, 2}

Range: {0, 1, 4}

Function: yes since all x-coordinates are different

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A six-sided number cube is weighted so that the number do not all have the same probability of landing up
Jobisdone [24]

Answer:

Ok so if this is a question then the probalility will probably be 1/3 for three of the 6 sides.

Step-by-step explanation:

3 0
3 years ago
Can someone plz tell me the answer and how to do this math problem?
olasank [31]
Start by taking away 22.36 from each side so that you are left with 4.73c = 42.57
And then divide each side by 4.73 so you will get c = 9
5 0
3 years ago
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A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em />cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

cos\theta is calculated as thus

cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0
3 years ago
Entre Celia y Quique suman 14€. Si Celia tuviera 1 €, tendría el doble de dinero que Quique.¿ Cuanto dinero tiene cada uno?
denpristay [2]

Answer:

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

Step-by-step explanation:

Representemos la cantidad de dinero

Celia tiene = x

Quique tiene = y

Entre Celia y Quique suman 14 €.

x + y = 14

x = 14 - y

Si Celia tuviera 1 euro, tendría el doble de dinero que Quique.

Por lo tanto,

x = 2 años

Nosotros sustituimos

2y + y = 14

3 años = 14

y = 14/3

y = 4.67 €

x = 14 € - y

x = 14 € - 4.67 €

x = 9.33 €

Por lo tanto,

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

7 0
3 years ago
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A ceramic tile in the shape of a parallelogram has a base of 4 inches and a height of 1.5 inches. What is the area of the tile?
kondor19780726 [428]

Answer:

6 in^2

Step-by-step explanation:

3 0
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