Here the time function is h(t) = [6 + 96t - 16t^2] feet.
The initial height of the ball is 6 feet. That's when t=0. h(0)=[6+0-0] ft = 6 ft.
At t=7 sec, h(t) = [6 + 96t - 16t^2] feet becomes
h(7 sec) = h(t) = [6 + 96(7) - 16(7)^2] feet This produces a large negative number (-106 ft), which in theory indicates that the ball has fallen to earth and burrowed 106 feet into the soil. Doesn't make sense.
Instead, let t=1 sec. Then h(1 sec) = h(t) = [6 + 96(1) - 16(1)^2] feet
=[6 + 96 -16] ft, or 86 ft.
One sec after the ball is thrown upward, it reaches a height of 86 feet. It continues to rise, slowing down, until it finally stops for an instant and then begins to fall towards earth.
Okay so you plug in 6.7 to M because that’s how far you are.
You are looking for T because it says seconds after.
So 6.7=t/4.6
then you multiply both sides by 4.6.
6.7x4.6=30.82.
So your answer is 30.82
The answer is 12. If you read from left to right, the numbers go up 12, if you go from right to left, they go down 12. Hope this helps!
Its all about process of elimination. Answer C
