KE=1/2(m)(v)^2
KE=1/2(80)(1.5)^2
KE=90 J
Answer:
Let the marked price be x
Discount % = 10%
Discount = 10\% \times x = 0.1x10%×x=0.1x
Cost after discount = x-0.1x = 0.9x
10%vat is charged on it
Cost including VAT = 0.9x+0.1(0.9x)=0.99x0.9x+0.1(0.9x)=0.99x
We are given that it's price became rs 1672
So, 0.99x = 1672
x=\frac{1672}{0.99}x=0.991672
x=1688.88
Discount = 0.1x=0.1(1688.88)=168.888
Hence The discount
<span>the series of xcosx is x summation from k = 0 to k = infinity of ((-1)^k x^2k)/(2k)!</span>
Answer:
26
Step-by-step explanation:
10+(10x3)-2(10-3)=
10+30+-2(7)=
40-14=
26
Domain is X and Range is Y
