The number of possible outcomes is 8.
The probability of getting exactly one tail is 3/8.
The probability of getting at most two tails is 3/4.
<h3>What are the probabilities?</h3>
Here is the sample space if 3 coins are tossed: {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}. There are 8 possible outcomes.
The probability of getting exactly one tail = number of times only one tail is gotten / total number of possible outcomes
3/8.
The probability of getting at most two tails = number of times at most two tails is gotten / total number of possible outcomes = 6/8 = 3/4
To learn more about probability, please check: brainly.com/question/13234031
#SPJ1
Answer:
-17+7i
Step-by-step explanation:
(-5)(8)+3 (blank) (-6)(7)+1
(-40)+3 (-42) +1
(-37) ( > ) (-41)
17 * 0 + -2.
Now we rewrite the equation and make it 17 * 0 - 2 and u get -2.
12 and 18 they each have 6 factors
