What is the volume if thr cone in cubic inches

Mathematics

1 answer:

kenny6666 [7]2 years ago

5 0

Answer:

27π in³ ≈ 84.8 in³

Step-by-step explanation:

The formula for the volume of a cone is ...

V = (1/3)πr²·h

where r represents the radius of the base of the cone, and h represents its height perpendicular to the base.

The diagram shows r = 3 in, and h = 9 in. Putting these numbers into the formula, we get ...

V = (1/3)π·(3 in)²·(9 in) = 27π in³

The volume is 27π in³, about 84.8 cubic inches.

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For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives <em>q</em> in terms of <em>p</em>, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$