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3 years ago

What is the volume if thr cone in cubic inches

Mathematics

1 answer:

kenny6666 [7]3 years ago

5 0

Answer:

27π in³ ≈ 84.8 in³

Step-by-step explanation:

The formula for the volume of a cone is ...

V = (1/3)πr²·h

where r represents the radius of the base of the cone, and h represents its height perpendicular to the base.

The diagram shows r = 3 in, and h = 9 in. Putting these numbers into the formula, we get ...

V = (1/3)π·(3 in)²·(9 in) = 27π in³

The volume is 27π in³, about 84.8 cubic inches.

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Explanation:

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So, the distance and slope of AB where A is (-5,3) and B is (0, 6) are:

$\begin{gathered} d=\sqrt[]{(0-(-5))^2+(6-3)^2} \\ d=\sqrt[]{(0+5)^2+3^2} \\ d=\sqrt[]{34} \\ m=\frac{6-3}{0-(-5)}=\frac{3}{0+5_{}}=\frac{3}{5} \end{gathered}$

The distance and slope of BC where B is (0,6) and C is (5, 3) are:

$\begin{gathered} d=\sqrt[]{(5-0)^2+(3-6)^2}=\sqrt[]{34} \\ m=\frac{3-6}{5-0}=-\frac{3}{5} \end{gathered}$

The distance and slope of CD where C is (5,3) and D is (0, 0) is:

$\begin{gathered} d=\sqrt[]{(0-5)^2+(0-3)^2}=\sqrt[]{34} \\ m=\frac{0-3}{0-5}=\frac{-3}{-5}=\frac{3}{5} \end{gathered}$

The distance and slope of AD where A is (-5,3) and D is (0, 0) are:

$\begin{gathered} d=\sqrt[]{(0-(-5))^2+(0-3)^2} \\ d=\sqrt[]{(0+5)^2+(3)^2}=\sqrt[]{34} \\ m=\frac{0-3}{0-(-5)}=-\frac{3}{5} \end{gathered}$

Therefore, the correct answers are:

Option 1 : Opposite sides (AB, CD, and BC, AD) have equal slopes making them parallel to each other, making ABCD a parallelogram.

Option 4: The distance of the sides AB, BC, CD, and AD are all congruent

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3 years ago

What is the volume if thr cone in cubic inches​

What is the volume if thr cone in cubic inches